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3-1.Vectors
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Three concurrent forces of the same magnitude are in equilibrium. What is the angle between the forces Also name the triangle formed by the forces as sides
A
$120^°$ equilateral triangle
B
$60^°$ equilateral triangle
C
$120^°, 30^°, 30^° $ an isosceles triangle
D
$120^°$ an obtuse angled triangle
Solution

(a) In $N$ forces of equal magnitude works on a single point and their resultant is zero then angle between any two forces is given
$\theta = \frac{{360}}{N}$$ = \frac{{360}}{3} = 120^\circ $
If these three vectors are represented by three sides of triangle then they form equilateral triangle
Standard 11
Physics