3-1.Vectors
medium

Three concurrent forces of the same magnitude are in equilibrium. What is the angle between the forces  Also name the triangle formed by the forces as sides

A

$120^°$ equilateral triangle

B

$60^°$ equilateral triangle

C

$120^°, 30^°, 30^° $ an isosceles triangle

D

$120^°$ an obtuse angled triangle

Solution

(a) In $N$ forces of equal magnitude works on a single point and their resultant is zero then angle between any two forces is given

$\theta = \frac{{360}}{N}$$ = \frac{{360}}{3} = 120^\circ $

If these three vectors are represented by three sides of triangle then they form equilateral triangle

Standard 11
Physics

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